I have selected 12 numbers in total, incuding 3 numbers that MUST be in all my lotto slips.
In order to have a more or less balanced selection, I chose:
- 3 even numbers ranging from 2 to 22,
- 3 odd numbers ranging from 1 to 21,
- 3 even numbers ranging from 24 to 44,
- 3 odd numbers ranging from 23 to 45.
- 1 number must be a repeat from the last draw: I chose 42 because it had not be drawn in the previous 27 draws;
- 1 cold number: I could have chosen 43 (only drawn 5 times), but since it came out in the last 2 draws, I selected number 1 instead (did not come out in the last 34 draws);
- 1 hot number: I picked the number 7 (drawn 22 times, it is the hottest number at the moment).
Here are the 12 numbers that I came up with (note the 3 highlighted red numbers that must be included):
1, 6, 7, 12, 20, 21, 23, 26, 27, 28, 42, 45.
I then made a spreadsheet including the numbers 1, 7 and 42 followed by all the possible combinations of the 9 remaining numbers, so that I have sets of 6 numbers (I found 86).
The next step is to add up the totals of all the numbers for each combination, and take out all sets that add up to less than 100 and all the sets that add up to more than 180 (I now have 80 sets of 6 numbers).
Now I want to eliminate the sets that have too many odd or too many even numbers; I will keep 2/4, 3/3 and 4/2. This leaves me with 74 combinations, which is far too many, so I need to take out more combinations.
The lowest possible combination is 1+2+3+4+5+6=21;
The highest possible combination is 45+44+43+42+41+40=255;
255+21=276;
276/2 =138------>average sum of all possible lotto combinations. I can see that the highest combination sum in my selected numbers equals 150 (which is 138+12), so I have decided to keep only the combinations that have sums ranging between 126 (138-12) and 150 (138+12).
I now have 25 combinations left, which is still too many to play with real money, but since I am still too chicken to actually buy the lotto tickets, it won't cost me anything to try them out. Since this is a 25 panel game, it would cost 25x€1.50=€37.50 to play this selection, so to make it worthwhile, a match 5 win would be nice. Now all I have to do is wait and see if I have any matching combinations (holding my breath until tonight, 8.00 pm).
Just for your information, here is my chosen selection:
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